What is the extreme h(v,t)=3vt-9t^2 ?

The extreme h(v,t)=3vt-9t^2 is Saddle(0,0)

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extreme h(v,t)=3vt-9t^2

extreme points

h (v, t) = 3 v t - 9 t^{2}

Saddle (0, 0)

Solution steps

Find the critical points:

(0, 0)

\frac{\partial ^{2} f}{\partial v ^{2}} = - 18

D (v, t) = - 9

Check the sign of at each critical point

Check critical point

(0, 0) :

Saddle

Saddle (0, 0)

f (x) = \frac{( 2 x - 9 )}{x}

f (x, y) = 400 - 9 x^{2} - 36 y^{2}

f (x) = (2 - x)^{2} (0 + x)

f (x, y) = \frac{- 4 x}{x ^{2} + y ^{2} + 1}

f (x, y) = x^{2} - 6 x + 10

What is the extreme h(v,t)=3vt-9t^2 ?
The extreme h(v,t)=3vt-9t^2 is Saddle(0,0)