What is the extreme f(x,y)=-2x^2+2xy-2x ?

The extreme f(x,y)=-2x^2+2xy-2x is Saddle(0,1)

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extreme f(x,y)=-2x^2+2xy-2x

extreme points

f (x, y) = - 2 x^{2} + 2 x y - 2 x

Saddle (0, 1)

Solution steps

Find the critical points:

(0, 1)

\frac{\partial ^{2} f}{\partial x ^{2}} = 0

D (x, y) = - 4

Check the sign of at each critical point

Check critical point

(0, 1) :

Saddle

Saddle (0, 1)

\frac{180 ln ( x ) - 300}{x ^{2}}

f (x, y) = x^{2} + y^{2} - 4

f (x) = a + 2 b = 53

F (x, y) = x^{3} - 4 x^{2} - x y - y^{2}

f (x) = x^{2} - 4 x - 7

What is the extreme f(x,y)=-2x^2+2xy-2x ?
The extreme f(x,y)=-2x^2+2xy-2x is Saddle(0,1)