What is the extreme f(x)=-34.3x^2+460.2x ?

The extreme f(x)=-34.3x^2+460.2x is Maximum(2301/343 ,1543.61545…)

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extreme f(x)=-34.3x^2+460.2x

extreme points

f (x) = - 34.3 x^{2} + 460.2 x

Maximum (\frac{2301}{343}, 1543.61545 \dots)

Solution steps

f^{'} (x) = - 68.6 x + 460.2

Find intervals:

Increasing

: - \infty < x < \frac{2301}{343},

Decreasing

: \frac{2301}{343} < x < \infty

Plug

x = \frac{2301}{343}

into

- 34.3 x^{2} + 460.2 x : 1543.61545 \dots

Maximum (\frac{2301}{343}, 1543.61545 \dots)

f (x) = - 3 (5 - 3 x) e^{- 4 x}, (- 1, 4)

f (x) = x^{3} - 6 x^{2} + 18

f (x) = 4 x + \frac{8}{x}

f (x) = - x^{2} + 229 x

f (x) = 6 x - 0.2 x^{2}, 0 \leq x \leq 30

What is the extreme f(x)=-34.3x^2+460.2x ?
The extreme f(x)=-34.3x^2+460.2x is Maximum(2301/343 ,1543.61545…)