What is the extreme f(x)=20(1+1/x+1/(x^2)) ?

The extreme f(x)=20(1+1/x+1/(x^2)) is Minimum(-2,15)

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extreme f(x)=20(1+1/x+1/(x^2))

extreme points

f (x) = 20 (1 + \frac{1}{x} + \frac{1}{x ^{2}})

Minimum (- 2, 15)

Solution steps

f^{'} (x) = 20 (- \frac{1}{x ^{2}} - \frac{2}{x ^{3}})

Find intervals:

Decreasing

: - \infty < x < - 2,

Increasing

: - 2 < x < 0,

Decreasing

: 0 < x < \infty

Plug

x = - 2

into

20 (1 + \frac{1}{x} + \frac{1}{x ^{2}}) : 15

Minimum (- 2, 15)

2 x^{2} - 2 x y + y^{2} - 2 x

f (x) = \frac{y - 1}{y ^{3} - y + 1}

f (x, y) = 2 x^{2} + 2 y^{2} - 16 x + 12 y

f (x) = x^{3} - 15 x^{2} + 63 x - 15

f (x, y) = \frac{8460}{x} + \frac{8460}{y} + 5 x y

What is the extreme f(x)=20(1+1/x+1/(x^2)) ?
The extreme f(x)=20(1+1/x+1/(x^2)) is Minimum(-2,15)