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Popular >

inflection f(x)= 2/7 x^3-2x+6

Solution

inflection points

f (x) = \frac{2}{7} x^{3} - 2 x + 6

Solution

(0, 6)

Solution steps

f^{''} (x) = \frac{12 x}{7}

Find intervals:

Concave Downward

: - \infty < x < 0,

Concave Upward

: 0 < x < \infty

Plug

x = 0

into

\frac{2}{7} x^{3} - 2 x + 6 : 6

(0, 6)

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domain of f(x)=((x+2)(x-1))/((x-3)^2)domain

f (x) = \frac{( x + 2 ) ( x - 1 )}{( x - 3 ) ^{2}}

f (x) = 2 x - 4

domain of f(x)=-3|7-2x|+4 domain

f (x) = - 3 ∣ 7 - 2 x ∣ + 4

Frequently Asked Questions (FAQ)

What is the inflection f(x)= 2/7 x^3-2x+6 ?
The inflection f(x)= 2/7 x^3-2x+6 is (0,6)