What is the extreme y=15xe^{-0.05x}-30 ?

The extreme y=15xe^{-0.05x}-30 is Maximum(20,(300)/e-30)

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extreme y=15xe^{-0.05x}-30

extreme points

y = 15 x e^{- 0.05 x} - 30

Maximum (20, \frac{300}{e} - 30)

Solution steps

f^{'} (x) = - 15 e^{- 0.05 x} (0.05 x - 1)

Find intervals:

Increasing

: - \infty < x < 20,

Decreasing

: 20 < x < \infty

Plug

x = 20

into

15 x e^{- 0.05 x} - 30 : \frac{300}{e} - 30

Maximum (20, \frac{300}{e} - 30)

f (x) = \frac{- 4 x}{x ^{2} + 6}, (0, 6)

f (x) = 2 x^{3} + 15 x^{2} - 36 x + 7, - 6 < x < 2

f (x) = 13 e^{- x}, (0, 4)

- y^{2} + 120 y

f (x) = x - \frac{1}{x} + \frac{2}{x ^{3}}, [0, \infty]

What is the extreme y=15xe^{-0.05x}-30 ?
The extreme y=15xe^{-0.05x}-30 is Maximum(20,(300)/e-30)