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Popular Functions >

extreme f(x)=(18)/((x^2-9))

Solution

extreme points

f (x) = \frac{18}{( x ^{2} - 9 )}

Solution

Maximum (0, - 2)

Solution steps

f^{'} (x) = - \frac{36 x}{( x ^{2} - 9 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < - 3,

Increasing

: - 3 < x < 0,

Decreasing

: 0 < x < 3,

Decreasing

: 3 < x < \infty

Plug

x = 0

into

\frac{18}{x ^{2} - 9} : - 2

Maximum (0, - 2)

Graph

Popular Examples

extreme f(x)=x^3-x^2-x+7,-1<= x<= 2 extreme points

f (x) = x^{3} - x^{2} - x + 7, - 1 \leq x \leq 2

extreme g(t)=8t-t^4 extreme points

g (t) = 8 t - t^{4}

extreme f(x,y)=-4xy(x+y)-9 extreme points

f (x, y) = - 4 x y (x + y) - 9

extreme f(x,y)=ln(10-x^2-y^2)extreme points

f (x, y) = ln (10 - x^{2} - y^{2})

extreme f(x)=(x^2-2x-3)/(x+5),-1<= x<= 3 extreme points

f (x) = \frac{x ^{2} - 2 x - 3}{x + 5}, - 1 \leq x \leq 3

Frequently Asked Questions (FAQ)

What is the extreme f(x)=(18)/((x^2-9)) ?
The extreme f(x)=(18)/((x^2-9)) is Maximum(0,-2)