extreme f(x)=0.002x^2+3.4x-20

Lösung

extrempunkte

f (x) = 0.002 x^{2} + 3.4 x - 20

Minimum (- 850, - 1465)

Schritte zur Lösung

f^{'} (x) = 0.004 x + 3.4

Intervalle finden:

Absteigend

: - \infty < x < - 850,

Ansteigend

: - 850 < x < \infty

Stecke

x = - 850

0.002 x^{2} + 3.4 x - 20 : - 1465

Minimum (- 850, - 1465)

e x t re m e f (x, y) = x^{3} + 2 y^{2} - 27 x - 8 y - 4

e x t re m e f (x) = x^{\frac{1}{3}} + 9

e x t re m e f (x) = (x^{2} + y^{2})^{2} = 2 \cdot (x^{2} - y^{2})

e x t re m e x^{3} + 3 x y^{2} - 3 x

e x t re m e f (x) = x^{\frac{2}{3}} (x - 2), - 2 \leq x \leq 2