What is the extreme f(x)=3-4x-4/x ?

The extreme f(x)=3-4x-4/x is Minimum(-1,11),Maximum(1,-5)

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extreme f(x)=3-4x-4/x

extreme

Minimum (- 1, 11), Maximum (1, - 5)

Solution steps

f^{'} (x) = \frac{4}{x ^{2}} - 4

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < 0,

Increasing

: 0 < x < 1,

Decreasing

: 1 < x < \infty

Plug

x = - 1

into

3 - 4 x - \frac{4}{x} : 11

Minimum (- 1, 11)

Plug

x = 1

into

3 - 4 x - \frac{4}{x} : - 5

Maximum (1, - 5)

Minimum (- 1, 11), Maximum (1, - 5)

What is the extreme f(x)=3-4x-4/x ?
The extreme f(x)=3-4x-4/x is Minimum(-1,11),Maximum(1,-5)