What is the extreme f(x)=*0.002d^2+0.7d+6.9 ?

The extreme f(x)=*0.002d^2+0.7d+6.9 is Minimum(-175,-54.35)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

extreme f(x)=*0.002d^2+0.7d+6.9

extreme

Minimum (- 175, - 54.35)

Solution steps

f^{'} (d) = 0.004 d + 0.7

Find intervals:

Decreasing

: - \infty < d < - 175,

Increasing

: - 175 < d < \infty

Plug

d = - 175

into

\cdot 0.002 d^{2} + 0.7 d + 6.9 : - 54.35

Minimum (- 175, - 54.35)

What is the extreme f(x)=*0.002d^2+0.7d+6.9 ?
The extreme f(x)=*0.002d^2+0.7d+6.9 is Minimum(-175,-54.35)