What is the extreme f(x)=2+4x+100x^{-1} ?

The extreme f(x)=2+4x+100x^{-1} is Maximum(-5,-38),Minimum(5,42)

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extreme f(x)=2+4x+100x^{-1}

extreme

Maximum (- 5, - 38), Minimum (5, 42)

Solution steps

f^{'} (x) = - \frac{100}{x ^{2}} + 4

Find intervals:

Increasing

: - \infty < x < - 5,

Decreasing

: - 5 < x < 0,

Decreasing

: 0 < x < 5,

Increasing

: 5 < x < \infty

Plug

x = - 5

into

2 + 4 x + 100 x^{- 1} : - 38

Maximum (- 5, - 38)

Plug

x = 5

into

2 + 4 x + 100 x^{- 1} : 42

Minimum (5, 42)

Maximum (- 5, - 38), Minimum (5, 42)

What is the extreme f(x)=2+4x+100x^{-1} ?
The extreme f(x)=2+4x+100x^{-1} is Maximum(-5,-38),Minimum(5,42)