What is the extreme f(x)=-2x^3+39x^2-240,4<= x<= 9 ?

The extreme f(x)=-2x^3+39x^2-240,4<= x<= 9 is Minimum(4,256),Maximum(9,1461)

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extreme f(x)=-2x^3+39x^2-240,4<= x<= 9

extreme

Minimum (4, 256), Maximum (9, 1461)

Solution steps

Find the critical points:

x = 4, x = 9

Domain of

- 2 x^{3} + 39 x^{2} - 240, 4 \leq x \leq 9 : 4 \leq x \leq 9

Find intervals:

Increasing

: 4 < x < 9

Plug the extreme point

x = 4

into

- 2 x^{3} + 39 x^{2} - 240 \Rightarrow y = 256

Minimum (4, 256)

Plug the extreme point

x = 9

into

- 2 x^{3} + 39 x^{2} - 240 \Rightarrow y = 1461

Maximum (9, 1461)

Minimum (4, 256), Maximum (9, 1461)

What is the extreme f(x)=-2x^3+39x^2-240,4<= x<= 9 ?
The extreme f(x)=-2x^3+39x^2-240,4<= x<= 9 is Minimum(4,256),Maximum(9,1461)