extreme x^3-27x+5

Lösung

extrempunkte

x^{3} - 27 x + 5

Maximum (- 3, 59), Minimum (3, - 49)

Schritte zur Lösung

f^{'} (x) = 3 x^{2} - 27

Intervalle finden:

Ansteigend

: - \infty < x < - 3,

Absteigend

: - 3 < x < 3,

Ansteigend

: 3 < x < \infty

Stecke

x = - 3

x^{3} - 27 x + 5 : 59

Maximum (- 3, 59)

Stecke

x = 3

x^{3} - 27 x + 5 : - 49

Minimum (3, - 49)

Maximum (- 3, 59), Minimum (3, - 49)

e x t re m e f (x, y) = x^{2} + x y + y^{2} + 4 x - 7 y + 6

e x t re m e f (x) = - 3 x^{2} - 5, - 4 \leq x \leq 3

e x t re m e f (x, y) = x^{2} + y^{2} + 8 x - 10 y

e x t re m e f (x) = ln (2 x^{2} - 2 x + 3), 0 \leq x \leq 2

e x t re m e f (x) = 5 - 6 x^{2}, - 4 \leq x \leq 2