What is the extreme f(x)=(2(x+6)^2)/(x+8) ?

The extreme f(x)=(2(x+6)^2)/(x+8) is Maximum(-10,-16),Minimum(-6,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

extreme f(x)=(2(x+6)^2)/(x+8)

extreme

Maximum (- 10, - 16), Minimum (- 6, 0)

Solution steps

f^{'} (x) = \frac{2 ( x ^{2} + 16 x + 60 )}{( x + 8 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < - 10,

Decreasing

: - 10 < x < - 8,

Decreasing

: - 8 < x < - 6,

Increasing

: - 6 < x < \infty

Plug

x = - 10

into

\frac{2 ( x + 6 ) ^{2}}{x + 8} : - 16

Maximum (- 10, - 16)

Plug

x = - 6

into

\frac{2 ( x + 6 ) ^{2}}{x + 8} : 0

Minimum (- 6, 0)

Maximum (- 10, - 16), Minimum (- 6, 0)

What is the extreme f(x)=(2(x+6)^2)/(x+8) ?
The extreme f(x)=(2(x+6)^2)/(x+8) is Maximum(-10,-16),Minimum(-6,0)