What is the extreme f(x)=10000e^{0.84(x-1.4)^2} ?

The extreme f(x)=10000e^{0.84(x-1.4)^2} is Minimum(1.4,10000)

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extreme f(x)=10000e^{0.84(x-1.4)^2}

extreme

Minimum (1.4, 10000)

Solution steps

f^{'} (x) = 16800 e^{0.84 (x - 1.4)^{2}} (x - 1.4)

Find intervals:

Decreasing

: - \infty < x < 1.4,

Increasing

: 1.4 < x < \infty

Plug

x = 1.4

into

10000 e^{0.84 (x - 1.4)^{2}} : 10000

Minimum (1.4, 10000)

What is the extreme f(x)=10000e^{0.84(x-1.4)^2} ?
The extreme f(x)=10000e^{0.84(x-1.4)^2} is Minimum(1.4,10000)