What is the extreme f(x)= x/(x^2+1)[-1.2] ?

The extreme f(x)= x/(x^2+1)[-1.2] is Maximum(-1,0.6),Minimum(1,-0.6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

extreme f(x)= x/(x^2+1)[-1.2]

extreme

Maximum (- 1, 0.6), Minimum (1, - 0.6)

Solution steps

Find the critical points:

x = - 1, x = 1

Domain of

\frac{x}{x ^{2} + 1} [- 1.2] : - \infty < x < \infty

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 1,

Increasing

: 1 < x < \infty

Plug the extreme point

x = - 1

into

\frac{x}{x ^{2} + 1} [- 1.2] \Rightarrow y = 0.6

Maximum (- 1, 0.6)

Plug the extreme point

x = 1

into

\frac{x}{x ^{2} + 1} [- 1.2] \Rightarrow y = - 0.6

Minimum (1, - 0.6)

Maximum (- 1, 0.6), Minimum (1, - 0.6)

What is the extreme f(x)= x/(x^2+1)[-1.2] ?
The extreme f(x)= x/(x^2+1)[-1.2] is Maximum(-1,0.6),Minimum(1,-0.6)