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Popular Functions >

extreme 2^{x^2-5}

Solution

extreme

Solution

Minimum (0, \frac{1}{32})

Solution steps

f^{'} (x) = ln (2) \cdot 2^{x^{2} - 4} x

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

2^{x^{2} - 5} : \frac{1}{32}

Minimum (0, \frac{1}{32})

Graph

Popular Examples

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extreme x^2-5a^2

extreme f(x)=3x+y-6

extreme f(x)=xe^{-3x},0<= x<= 2

Frequently Asked Questions (FAQ)

What is the extreme 2^{x^2-5} ?
The extreme 2^{x^2-5} is Minimum(0, 1/32)