What is the extreme f(x)=((x^4+1))/(x^2) ?

The extreme f(x)=((x^4+1))/(x^2) is Minimum(-1,2),Minimum(1,2)

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extreme f(x)=((x^4+1))/(x^2)

extreme

Minimum (- 1, 2), Minimum (1, 2)

Solution steps

f^{'} (x) = \frac{2 ( x ^{4} - 1 )}{x ^{3}}

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < 0,

Decreasing

: 0 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 1

into

\frac{x ^{4} + 1}{x ^{2}} : 2

Minimum (- 1, 2)

Plug

x = 1

into

\frac{x ^{4} + 1}{x ^{2}} : 2

Minimum (1, 2)

Minimum (- 1, 2), Minimum (1, 2)

What is the extreme f(x)=((x^4+1))/(x^2) ?
The extreme f(x)=((x^4+1))/(x^2) is Minimum(-1,2),Minimum(1,2)