What is the extreme f(x)=-20x^2-70x+120 ?

The extreme f(x)=-20x^2-70x+120 is Maximum(-7/4 , 725/4)

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extreme f(x)=-20x^2-70x+120

extreme

Maximum (- \frac{7}{4}, \frac{725}{4})

Solution steps

f^{'} (x) = - 40 x - 70

Find intervals:

Increasing

: - \infty < x < - \frac{7}{4},

Decreasing

: - \frac{7}{4} < x < \infty

Plug

x = - \frac{7}{4}

into

- 20 x^{2} - 70 x + 120 : \frac{725}{4}

Maximum (- \frac{7}{4}, \frac{725}{4})

What is the extreme f(x)=-20x^2-70x+120 ?
The extreme f(x)=-20x^2-70x+120 is Maximum(-7/4 , 725/4)