What is the extreme f(x,y)=-7x^2+5y^2-4x-5y+5 ?

The extreme f(x,y)=-7x^2+5y^2-4x-5y+5 is Saddle(-2/7 , 1/2)

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extreme f(x,y)=-7x^2+5y^2-4x-5y+5

extreme

Saddle (- \frac{2}{7}, \frac{1}{2})

Solution steps

Find the critical points:

(- \frac{2}{7}, \frac{1}{2})

\frac{\partial ^{2} f}{\partial x ^{2}} = 10

D (x, y) = - 140

Check the sign of at each critical point

Check critical point

(- \frac{2}{7}, \frac{1}{2}) :

Saddle

Saddle (- \frac{2}{7}, \frac{1}{2})

What is the extreme f(x,y)=-7x^2+5y^2-4x-5y+5 ?
The extreme f(x,y)=-7x^2+5y^2-4x-5y+5 is Saddle(-2/7 , 1/2)