What is the extreme y= x/(x^2+4),(-3,1) ?

The extreme y= x/(x^2+4),(-3,1) is Minimum(-2,-1/4)

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extreme y= x/(x^2+4),(-3,1)

extreme

Minimum (- 2, - \frac{1}{4})

Solution steps

Find the critical points:

x = - 2

Domain of

\frac{x}{x ^{2} + 4}, (- 3, 1) : - 3 < x < 1

Find intervals:

Decreasing

: - 3 < x < - 2,

Increasing

: - 2 < x < 1

Plug the extreme point

x = - 2

into

\frac{x}{x ^{2} + 4} \Rightarrow y = - \frac{1}{4}

Minimum (- 2, - \frac{1}{4})

What is the extreme y= x/(x^2+4),(-3,1) ?
The extreme y= x/(x^2+4),(-3,1) is Minimum(-2,-1/4)