What is the extreme f(x)=5+2x+8x^{-1} ?

The extreme f(x)=5+2x+8x^{-1} is Maximum(-2,-3),Minimum(2,13)

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extreme f(x)=5+2x+8x^{-1}

extreme

Maximum (- 2, - 3), Minimum (2, 13)

Solution steps

f^{'} (x) = - \frac{8}{x ^{2}} + 2

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 0,

Decreasing

: 0 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 2

into

5 + 2 x + 8 x^{- 1} : - 3

Maximum (- 2, - 3)

Plug

x = 2

into

5 + 2 x + 8 x^{- 1} : 13

Minimum (2, 13)

Maximum (- 2, - 3), Minimum (2, 13)

What is the extreme f(x)=5+2x+8x^{-1} ?
The extreme f(x)=5+2x+8x^{-1} is Maximum(-2,-3),Minimum(2,13)