What is the extreme 20-0.06x+0.0002x^2 ?

The extreme 20-0.06x+0.0002x^2 is Minimum((0.06)/(0.0004),15.5)

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extreme 20-0.06x+0.0002x^2

extreme

Minimum (\frac{0.06}{0.0004}, 15.5)

Solution steps

f^{'} (x) = 0.0004 x - 0.06

Find intervals:

Decreasing

: - \infty < x < \frac{0.06}{0.0004},

Increasing

: \frac{0.06}{0.0004} < x < \infty

Plug

x = \frac{0.06}{0.0004}

into

20 - 0.06 x + 0.0002 x^{2} : 15.5

Minimum (\frac{0.06}{0.0004}, 15.5)

What is the extreme 20-0.06x+0.0002x^2 ?
The extreme 20-0.06x+0.0002x^2 is Minimum((0.06)/(0.0004),15.5)