What is the extreme f(x)=\sqrt[3]{x},-27<= x<= 8 ?

The extreme f(x)=\sqrt[3]{x},-27<= x<= 8 is Minimum(-27,-3),Maximum(8,2)

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extreme f(x)=\sqrt[3]{x},-27<= x<= 8

extreme

Minimum (- 27, - 3), Maximum (8, 2)

Solution steps

Find the critical points:

x = - 27, x = 0, x = 8

Domain of

3 x, - 27 \leq x \leq 8 : - 27 \leq x \leq 8

Find intervals:

Increasing

: - 27 < x < 0,

Increasing

: 0 < x < 8

Plug the extreme point

x = - 27

into

3 x \Rightarrow y = - 3

Minimum (- 27, - 3)

Plug the extreme point

x = 8

into

3 x \Rightarrow y = 2

Maximum (8, 2)

Minimum (- 27, - 3), Maximum (8, 2)

What is the extreme f(x)=\sqrt[3]{x},-27<= x<= 8 ?
The extreme f(x)=\sqrt[3]{x},-27<= x<= 8 is Minimum(-27,-3),Maximum(8,2)