What is the extreme 2x^3-x^2-4x+12 ?

The extreme 2x^3-x^2-4x+12 is Maximum(-2/3 , 368/27),Minimum(1,9)

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extreme 2x^3-x^2-4x+12

extreme

Maximum (- \frac{2}{3}, \frac{368}{27}), Minimum (1, 9)

Solution steps

f^{'} (x) = 6 x^{2} - 2 x - 4

Find intervals:

Increasing

: - \infty < x < - \frac{2}{3},

Decreasing

: - \frac{2}{3} < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - \frac{2}{3}

into

2 x^{3} - x^{2} - 4 x + 12 : \frac{368}{27}

Maximum (- \frac{2}{3}, \frac{368}{27})

Plug

x = 1

into

2 x^{3} - x^{2} - 4 x + 12 : 9

Minimum (1, 9)

Maximum (- \frac{2}{3}, \frac{368}{27}), Minimum (1, 9)

What is the extreme 2x^3-x^2-4x+12 ?
The extreme 2x^3-x^2-4x+12 is Maximum(-2/3 , 368/27),Minimum(1,9)