What is the extreme f(x)=(3-5x)e^{2x} ?

The extreme f(x)=(3-5x)e^{2x} is Maximum(1/10 ,(5e^{1/5})/2)

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extreme f(x)=(3-5x)e^{2x}

extreme

Maximum (\frac{1}{10}, \frac{5 e ^{\frac{1}{5}}}{2})

Solution steps

f^{'} (x) = e^{2 x} (- 10 x + 1)

Find intervals:

Increasing

: - \infty < x < \frac{1}{10},

Decreasing

: \frac{1}{10} < x < \infty

Plug

x = \frac{1}{10}

into

(3 - 5 x) e^{2 x} : \frac{5 e ^{\frac{1}{5}}}{2}

Maximum (\frac{1}{10}, \frac{5 e ^{\frac{1}{5}}}{2})

What is the extreme f(x)=(3-5x)e^{2x} ?
The extreme f(x)=(3-5x)e^{2x} is Maximum(1/10 ,(5e^{1/5})/2)