What is the extreme y=\sqrt[3]{5x^3+5} ?

The extreme y=\sqrt[3]{5x^3+5} is Saddle(0,\sqrt[3]{5})

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extreme y=\sqrt[3]{5x^3+5}

extreme

Saddle (0, 35)

Solution steps

f^{'} (x) = \frac{5 x ^{2}}{( 5 x ^{3} + 5 ) ^{\frac{2}{3}}}

Find intervals:

Increasing

: - \infty < x < - 1,

Increasing

: - 1 < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

3 5 x^{3} + 5 : 35

Saddle (0, 35)

What is the extreme y=\sqrt[3]{5x^3+5} ?
The extreme y=\sqrt[3]{5x^3+5} is Saddle(0,\sqrt[3]{5})