What is the extreme f(x)=-0.001x^2+4.2x-10 ?

The extreme f(x)=-0.001x^2+4.2x-10 is Maximum(2100,4400)

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extreme f(x)=-0.001x^2+4.2x-10

extreme

Maximum (2100, 4400)

Solution steps

f^{'} (x) = - 0.002 x + 4.2

Find intervals:

Increasing

: - \infty < x < 2100,

Decreasing

: 2100 < x < \infty

Plug

x = 2100

into

- 0.001 x^{2} + 4.2 x - 10 : 4400

Maximum (2100, 4400)

What is the extreme f(x)=-0.001x^2+4.2x-10 ?
The extreme f(x)=-0.001x^2+4.2x-10 is Maximum(2100,4400)