What is the extreme f(x,y)=2x^2+3y^2-4x-12y+13 ?

The extreme f(x,y)=2x^2+3y^2-4x-12y+13 is Minimum(1,2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

extreme f(x,y)=2x^2+3y^2-4x-12y+13

extreme

Minimum (1, 2)

Solution steps

Find the critical points:

(1, 2)

\frac{\partial ^{2} f}{\partial x ^{2}} = 6

D (x, y) = 24

Check the sign of at each critical point

Check critical point

(1, 2) :

Minimum

Minimum (1, 2)

What is the extreme f(x,y)=2x^2+3y^2-4x-12y+13 ?
The extreme f(x,y)=2x^2+3y^2-4x-12y+13 is Minimum(1,2)