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Popular Functions >

extreme (64)/(x^2+6x-7)

Solution

extreme

Solution

Maximum (- 3, - 4)

Solution steps

f^{'} (x) = - \frac{64 ( 2 x + 6 )}{( x ^{2} + 6 x - 7 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < - 7,

Increasing

: - 7 < x < - 3,

Decreasing

: - 3 < x < 1,

Decreasing

: 1 < x < \infty

Plug

x = - 3

into

\frac{64}{x ^{2} + 6 x - 7} : - 4

Maximum (- 3, - 4)

Graph

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Frequently Asked Questions (FAQ)

What is the extreme (64)/(x^2+6x-7) ?
The extreme (64)/(x^2+6x-7) is Maximum(-3,-4)