What is the extreme f(x)=x^2-2x,1<= x<= 4 ?

The extreme f(x)=x^2-2x,1<= x<= 4 is Minimum(1,-1),Maximum(4,8)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

extreme f(x)=x^2-2x,1<= x<= 4

extreme

Minimum (1, - 1), Maximum (4, 8)

Solution steps

Find the critical points:

x = 1, x = 4

Domain of

x^{2} - 2 x, 1 \leq x \leq 4 : 1 \leq x \leq 4

Find intervals:

Increasing

: 1 < x < 4

Plug the extreme point

x = 1

into

x^{2} - 2 x \Rightarrow y = - 1

Minimum (1, - 1)

Plug the extreme point

x = 4

into

x^{2} - 2 x \Rightarrow y = 8

Maximum (4, 8)

Minimum (1, - 1), Maximum (4, 8)

What is the extreme f(x)=x^2-2x,1<= x<= 4 ?
The extreme f(x)=x^2-2x,1<= x<= 4 is Minimum(1,-1),Maximum(4,8)