What is the extreme f(x)=(2(x+7)^2)/(x+10),(-10,-6) ?

The extreme f(x)=(2(x+7)^2)/(x+10),(-10,-6) is Minimum(-7,0)

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extreme f(x)=(2(x+7)^2)/(x+10),(-10,-6)

extreme

Minimum (- 7, 0)

Solution steps

Find the critical points:

x = - 7

Domain of

\frac{2 ( x + 7 ) ^{2}}{x + 10}, (- 10, - 6) : - 10 < x < - 6

Find intervals:

Decreasing

: - 10 < x < - 7,

Increasing

: - 7 < x < - 6

Plug the extreme point

x = - 7

into

\frac{2 ( x + 7 ) ^{2}}{x + 10} \Rightarrow y = 0

Minimum (- 7, 0)

What is the extreme f(x)=(2(x+7)^2)/(x+10),(-10,-6) ?
The extreme f(x)=(2(x+7)^2)/(x+10),(-10,-6) is Minimum(-7,0)