What is the extreme f(x)=(x-4)ln(x-4) ?

The extreme f(x)=(x-4)ln(x-4) is Minimum(1/e+4,-1/e)

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extreme f(x)=(x-4)ln(x-4)

extreme

Minimum (\frac{1}{e} + 4, - \frac{1}{e})

Solution steps

f^{'} (x) = ln (x - 4) + 1

Find intervals:

Decreasing

: 4 < x < \frac{1}{e} + 4,

Increasing

: \frac{1}{e} + 4 < x < \infty

Plug

x = \frac{1}{e} + 4

into

(x - 4) ln (x - 4) : - \frac{1}{e}

Minimum (\frac{1}{e} + 4, - \frac{1}{e})

What is the extreme f(x)=(x-4)ln(x-4) ?
The extreme f(x)=(x-4)ln(x-4) is Minimum(1/e+4,-1/e)