What is the extreme f(x)=((x-1)^2)/(x-3) ?

The extreme f(x)=((x-1)^2)/(x-3) is Maximum(1,0),Minimum(5,8)

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extreme f(x)=((x-1)^2)/(x-3)

extreme

Maximum (1, 0), Minimum (5, 8)

Solution steps

f^{'} (x) = \frac{x ^{2} - 6 x + 5}{( x - 3 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < 1,

Decreasing

: 1 < x < 3,

Decreasing

: 3 < x < 5,

Increasing

: 5 < x < \infty

Plug

x = 1

into

\frac{( x - 1 ) ^{2}}{x - 3} : 0

Maximum (1, 0)

Plug

x = 5

into

\frac{( x - 1 ) ^{2}}{x - 3} : 8

Minimum (5, 8)

Maximum (1, 0), Minimum (5, 8)

What is the extreme f(x)=((x-1)^2)/(x-3) ?
The extreme f(x)=((x-1)^2)/(x-3) is Maximum(1,0),Minimum(5,8)