What is the extreme f(x)=x^4-18x^2-3 ?

The extreme f(x)=x^4-18x^2-3 is Minimum(-3,-84),Maximum(0,-3),Minimum(3,-84)

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extreme f(x)=x^4-18x^2-3

extreme

Minimum (- 3, - 84), Maximum (0, - 3), Minimum (3, - 84)

Solution steps

f^{'} (x) = 4 x^{3} - 36 x

Find intervals:

Decreasing

: - \infty < x < - 3,

Increasing

: - 3 < x < 0,

Decreasing

: 0 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 3

into

x^{4} - 18 x^{2} - 3 : - 84

Minimum (- 3, - 84)

Plug

x = 0

into

x^{4} - 18 x^{2} - 3 : - 3

Maximum (0, - 3)

Plug

x = 3

into

x^{4} - 18 x^{2} - 3 : - 84

Minimum (3, - 84)

Minimum (- 3, - 84), Maximum (0, - 3), Minimum (3, - 84)

What is the extreme f(x)=x^4-18x^2-3 ?
The extreme f(x)=x^4-18x^2-3 is Minimum(-3,-84),Maximum(0,-3),Minimum(3,-84)