What is the extreme f(x)=2x^3-36x^2+120x+2 ?

The extreme f(x)=2x^3-36x^2+120x+2 is Maximum(2,114),Minimum(10,-398)

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extreme f(x)=2x^3-36x^2+120x+2

extreme

Maximum (2, 114), Minimum (10, - 398)

Solution steps

f^{'} (x) = 6 x^{2} - 72 x + 120

Find intervals:

Increasing

: - \infty < x < 2,

Decreasing

: 2 < x < 10,

Increasing

: 10 < x < \infty

Plug

x = 2

into

2 x^{3} - 36 x^{2} + 120 x + 2 : 114

Maximum (2, 114)

Plug

x = 10

into

2 x^{3} - 36 x^{2} + 120 x + 2 : - 398

Minimum (10, - 398)

Maximum (2, 114), Minimum (10, - 398)

What is the extreme f(x)=2x^3-36x^2+120x+2 ?
The extreme f(x)=2x^3-36x^2+120x+2 is Maximum(2,114),Minimum(10,-398)