What is the extreme f(x)=(x^2-2x+1)/(x-2) ?

The extreme f(x)=(x^2-2x+1)/(x-2) is Maximum(1,0),Minimum(3,4)

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extreme f(x)=(x^2-2x+1)/(x-2)

extreme

Maximum (1, 0), Minimum (3, 4)

Solution steps

f^{'} (x) = \frac{x ^{2} - 4 x + 3}{( x - 2 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < 1,

Decreasing

: 1 < x < 2,

Decreasing

: 2 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = 1

into

\frac{x ^{2} - 2 x + 1}{x - 2} : 0

Maximum (1, 0)

Plug

x = 3

into

\frac{x ^{2} - 2 x + 1}{x - 2} : 4

Minimum (3, 4)

Maximum (1, 0), Minimum (3, 4)

What is the extreme f(x)=(x^2-2x+1)/(x-2) ?
The extreme f(x)=(x^2-2x+1)/(x-2) is Maximum(1,0),Minimum(3,4)