What is the extreme f(x)=2x^3-39x^2+240x-9 ?

The extreme f(x)=2x^3-39x^2+240x-9 is Maximum(5,466),Minimum(8,439)

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extreme f(x)=2x^3-39x^2+240x-9

extreme

Maximum (5, 466), Minimum (8, 439)

Solution steps

f^{'} (x) = 6 x^{2} - 78 x + 240

Find intervals:

Increasing

: - \infty < x < 5,

Decreasing

: 5 < x < 8,

Increasing

: 8 < x < \infty

Plug

x = 5

into

2 x^{3} - 39 x^{2} + 240 x - 9 : 466

Maximum (5, 466)

Plug

x = 8

into

2 x^{3} - 39 x^{2} + 240 x - 9 : 439

Minimum (8, 439)

Maximum (5, 466), Minimum (8, 439)

What is the extreme f(x)=2x^3-39x^2+240x-9 ?
The extreme f(x)=2x^3-39x^2+240x-9 is Maximum(5,466),Minimum(8,439)