What is the extreme y=(x-1)^2(x+1) ?

The extreme y=(x-1)^2(x+1) is Maximum(-1/3 , 32/27),Minimum(1,0)

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extreme y=(x-1)^2(x+1)

extreme

Maximum (- \frac{1}{3}, \frac{32}{27}), Minimum (1, 0)

Solution steps

f^{'} (x) = (x - 1) (3 x + 1)

Find intervals:

Increasing

: - \infty < x < - \frac{1}{3},

Decreasing

: - \frac{1}{3} < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - \frac{1}{3}

into

(x - 1)^{2} (x + 1) : \frac{32}{27}

Maximum (- \frac{1}{3}, \frac{32}{27})

Plug

x = 1

into

(x - 1)^{2} (x + 1) : 0

Minimum (1, 0)

Maximum (- \frac{1}{3}, \frac{32}{27}), Minimum (1, 0)

What is the extreme y=(x-1)^2(x+1) ?
The extreme y=(x-1)^2(x+1) is Maximum(-1/3 , 32/27),Minimum(1,0)