What is the extreme f(x)=2x^3-x^2-4x-6 ?

The extreme f(x)=2x^3-x^2-4x-6 is Maximum(-2/3 ,-118/27),Minimum(1,-9)

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extreme f(x)=2x^3-x^2-4x-6

extreme

Maximum (- \frac{2}{3}, - \frac{118}{27}), Minimum (1, - 9)

Solution steps

f^{'} (x) = 6 x^{2} - 2 x - 4

Find intervals:

Increasing

: - \infty < x < - \frac{2}{3},

Decreasing

: - \frac{2}{3} < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - \frac{2}{3}

into

2 x^{3} - x^{2} - 4 x - 6 : - \frac{118}{27}

Maximum (- \frac{2}{3}, - \frac{118}{27})

Plug

x = 1

into

2 x^{3} - x^{2} - 4 x - 6 : - 9

Minimum (1, - 9)

Maximum (- \frac{2}{3}, - \frac{118}{27}), Minimum (1, - 9)

What is the extreme f(x)=2x^3-x^2-4x-6 ?
The extreme f(x)=2x^3-x^2-4x-6 is Maximum(-2/3 ,-118/27),Minimum(1,-9)