What is the extreme f(x)=2x^3-18x^2+48x-7 ?

The extreme f(x)=2x^3-18x^2+48x-7 is Maximum(2,33),Minimum(4,25)

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extreme f(x)=2x^3-18x^2+48x-7

extreme

Maximum (2, 33), Minimum (4, 25)

Solution steps

f^{'} (x) = 6 x^{2} - 36 x + 48

Find intervals:

Increasing

: - \infty < x < 2,

Decreasing

: 2 < x < 4,

Increasing

: 4 < x < \infty

Plug

x = 2

into

2 x^{3} - 18 x^{2} + 48 x - 7 : 33

Maximum (2, 33)

Plug

x = 4

into

2 x^{3} - 18 x^{2} + 48 x - 7 : 25

Minimum (4, 25)

Maximum (2, 33), Minimum (4, 25)

What is the extreme f(x)=2x^3-18x^2+48x-7 ?
The extreme f(x)=2x^3-18x^2+48x-7 is Maximum(2,33),Minimum(4,25)