What is the extreme g(x)=xsqrt(18-x) ?

The extreme g(x)=xsqrt(18-x) is Maximum(12,12sqrt(6)),Minimum(18,0)

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extreme g(x)=xsqrt(18-x)

extreme

Maximum (12, 126), Minimum (18, 0)

Solution steps

f^{'} (x) = - \frac{3 ( x - 12 )}{2 18 - x}

Find intervals:

Increasing

: - \infty < x < 12,

Decreasing

: 12 < x < 18

Plug

x = 12

into

x 18 - x : 126

Maximum (12, 126)

Plug

x = 18

into

x 18 - x : 0

Minimum (18, 0)

Maximum (12, 126), Minimum (18, 0)

What is the extreme g(x)=xsqrt(18-x) ?
The extreme g(x)=xsqrt(18-x) is Maximum(12,12sqrt(6)),Minimum(18,0)