What is the extreme f(x)=2x^3-3x^2-12 ?

The extreme f(x)=2x^3-3x^2-12 is Maximum(0,-12),Minimum(1,-13)

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extreme f(x)=2x^3-3x^2-12

extreme

Maximum (0, - 12), Minimum (1, - 13)

Solution steps

f^{'} (x) = 6 x^{2} - 6 x

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = 0

into

2 x^{3} - 3 x^{2} - 12 : - 12

Maximum (0, - 12)

Plug

x = 1

into

2 x^{3} - 3 x^{2} - 12 : - 13

Minimum (1, - 13)

Maximum (0, - 12), Minimum (1, - 13)

What is the extreme f(x)=2x^3-3x^2-12 ?
The extreme f(x)=2x^3-3x^2-12 is Maximum(0,-12),Minimum(1,-13)