What is the extreme f(x)=-69.7x^2+625.6x ?

The extreme f(x)=-69.7x^2+625.6x is Maximum(184/41 ,1403.78536…)

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extreme f(x)=-69.7x^2+625.6x

extreme

Maximum (\frac{184}{41}, 1403.78536 \dots)

Solution steps

f^{'} (x) = - 139.4 x + 625.6

Find intervals:

Increasing

: - \infty < x < \frac{184}{41},

Decreasing

: \frac{184}{41} < x < \infty

Plug

x = \frac{184}{41}

into

- 69.7 x^{2} + 625.6 x : 1403.78536 \dots

Maximum (\frac{184}{41}, 1403.78536 \dots)

What is the extreme f(x)=-69.7x^2+625.6x ?
The extreme f(x)=-69.7x^2+625.6x is Maximum(184/41 ,1403.78536…)