What is the extreme f(x)=tan((pix)/(20)),0<= x<= 5 ?

The extreme f(x)=tan((pix)/(20)),0<= x<= 5 is Minimum(0,0),Maximum(5,1)

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extreme f(x)=tan((pix)/(20)),0<= x<= 5

extreme

Minimum (0, 0), Maximum (5, 1)

Solution steps

Find the critical points:

x = 0, x = 5

Domain of

tan (\frac{π x}{20}), 0 \leq x \leq 5 : 0 \leq x \leq 5

Find intervals:

Increasing

: 0 < x < 5

Plug the extreme point

x = 0

into

tan (\frac{π x}{20}) \Rightarrow y = 0

Minimum (0, 0)

Plug the extreme point

x = 5

into

tan (\frac{π x}{20}) \Rightarrow y = 1

Maximum (5, 1)

Minimum (0, 0), Maximum (5, 1)

What is the extreme f(x)=tan((pix)/(20)),0<= x<= 5 ?
The extreme f(x)=tan((pix)/(20)),0<= x<= 5 is Minimum(0,0),Maximum(5,1)