What is the extreme f(x)=x(18-48+2x)(48/2-x) ?

The extreme f(x)=x(18-48+2x)(48/2-x) is Minimum(6,-1944),Maximum(20,800)

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extreme f(x)=x(18-48+2x)(48/2-x)

extreme

Minimum (6, - 1944), Maximum (20, 800)

Solution steps

f^{'} (x) = - 6 (x - 6) (x - 20)

Find intervals:

Decreasing

: - \infty < x < 6,

Increasing

: 6 < x < 20,

Decreasing

: 20 < x < \infty

Plug

x = 6

into

x (18 - 48 + 2 x) (\frac{48}{2} - x) : - 1944

Minimum (6, - 1944)

Plug

x = 20

into

x (18 - 48 + 2 x) (\frac{48}{2} - x) : 800

Maximum (20, 800)

Minimum (6, - 1944), Maximum (20, 800)

What is the extreme f(x)=x(18-48+2x)(48/2-x) ?
The extreme f(x)=x(18-48+2x)(48/2-x) is Minimum(6,-1944),Maximum(20,800)