What is the extreme f(x)=x^3-6x^2+5[-3.5] ?

The extreme f(x)=x^3-6x^2+5[-3.5] is Maximum(0,-17.5),Minimum(4,-49.5)

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extreme f(x)=x^3-6x^2+5[-3.5]

extreme

Maximum (0, - 17.5), Minimum (4, - 49.5)

Solution steps

f^{'} (x) = 3 x^{2} - 12 x

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < 4,

Increasing

: 4 < x < \infty

Plug

x = 0

into

x^{3} - 6 x^{2} + 5 [- 3.5] : - 17.5

Maximum (0, - 17.5)

Plug

x = 4

into

x^{3} - 6 x^{2} + 5 [- 3.5] : - 49.5

Minimum (4, - 49.5)

Maximum (0, - 17.5), Minimum (4, - 49.5)

What is the extreme f(x)=x^3-6x^2+5[-3.5] ?
The extreme f(x)=x^3-6x^2+5[-3.5] is Maximum(0,-17.5),Minimum(4,-49.5)