What is the extreme f(x)=((2x^3+5x))/((x+7)) ?

The extreme f(x)=((2x^3+5x))/((x+7)) is Minimum(-10.57819…,676.38939…)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

extreme f(x)=((2x^3+5x))/((x+7))

extreme

Minimum (- 10.57819 \dots, 676.38939 \dots)

Solution steps

Find the critical points:

x \approx - 10.57819 \dots

Domain of

\frac{2 x ^{3} + 5 x}{x + 7} : x < - 7 or x > - 7

Find intervals:

Decreasing

: - \infty < x < - 10.57819 \dots,

Increasing

: - 10.57819 \dots < x < - 7,

Increasing

: - 7 < x < \infty

Plug the extreme point

x = - 10.57819 \dots

into

\frac{2 x ^{3} + 5 x}{x + 7} \Rightarrow y = 676.38939 \dots

Minimum (- 10.57819 \dots, 676.38939 \dots)

What is the extreme f(x)=((2x^3+5x))/((x+7)) ?
The extreme f(x)=((2x^3+5x))/((x+7)) is Minimum(-10.57819…,676.38939…)