What is the extreme f(x)=sin(11x) ?

The extreme f(x)=sin(11x) is Maximum(pi/(22)+(2pi)/(11)n,1),Minimum((3pi)/(22)+(2pi)/(11)n,-1)

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extreme f(x)=sin(11x)

extreme

Maximum (\frac{π}{22} + \frac{2 π}{11} n, 1), Minimum (\frac{3 π}{22} + \frac{2 π}{11} n, - 1)

Solution steps

Find the critical points:

x = \frac{π}{22} + \frac{2 π}{11} n, x = \frac{3 π}{22} + \frac{2 π}{11} n

Domain of

sin (11 x) : - \infty < x < \infty

Find intervals:

Increasing

: \frac{2 π}{11} n \leq x < \frac{π}{22} + \frac{2 π}{11} n,

Decreasing

: \frac{π}{22} + \frac{2 π}{11} n < x < \frac{3 π}{22} + \frac{2 π}{11} n,

Increasing

: \frac{3 π}{22} + \frac{2 π}{11} n < x < \frac{2 π}{11} + \frac{2 π}{11} n

Plug the extreme point

x = \frac{π}{22} + \frac{2 π}{11} n

into

sin (11 x) \Rightarrow y = 1

Maximum (\frac{π}{22} + \frac{2 π}{11} n, 1)

Plug the extreme point

x = \frac{3 π}{22} + \frac{2 π}{11} n

into

sin (11 x) \Rightarrow y = - 1

Minimum (\frac{3 π}{22} + \frac{2 π}{11} n, - 1)

Maximum (\frac{π}{22} + \frac{2 π}{11} n, 1), Minimum (\frac{3 π}{22} + \frac{2 π}{11} n, - 1)

What is the extreme f(x)=sin(11x) ?
The extreme f(x)=sin(11x) is Maximum(pi/(22)+(2pi)/(11)n,1),Minimum((3pi)/(22)+(2pi)/(11)n,-1)