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Popular Functions >

extreme f(x)=2x^2+7x

Solution

extreme

Solution

Minimum (- \frac{7}{4}, - \frac{49}{8})

Solution steps

f^{'} (x) = 4 x + 7

Find intervals:

Decreasing

: - \infty < x < - \frac{7}{4},

Increasing

: - \frac{7}{4} < x < \infty

Plug

x = - \frac{7}{4}

into

2 x^{2} + 7 x : - \frac{49}{8}

Minimum (- \frac{7}{4}, - \frac{49}{8})

Graph

Popular Examples

extreme f(x)=(x^2+3x+9),-2<= x<= 1

extreme f(x)=4x^3-x^2-x+8

extreme f(x,y)=sqrt(400-16x^2-25y^2)

Frequently Asked Questions (FAQ)

What is the extreme f(x)=2x^2+7x ?
The extreme f(x)=2x^2+7x is Minimum(-7/4 ,-49/8)